X, Y, and Z are hired to complete a project for Tk. 6900. X and Y together complete 17/25 of the work, and Y and Z together complete 13/25 of the work. What is the wage of Y in Taka?
A
Tk. 1380
B
Tk. 1460
C
Tk. 1650
D
Tk. 1250
উত্তরের বিবরণ
Question: X, Y, and Z are hired to complete a project for Tk. 6900. X and Y together complete 17/25 of the work, and Y and Z together complete 13/25 of the work. What is the wage of Y in Taka?
Solution:
X + Y = 17/25
Y + Z = 13/25
অতএব,
X + Y + Y + Z = (17/25) + (13/25)
= 30/25
যেখানে, X + Y + Z = 1 (সম্পূর্ণ কাজ)
এখন,
(X + Y + Z + Y) - (X + Y + Z) = 30/25 - 1
∴ Y = 5/25 = 1/5
∴ Y এর বেতন = (1/5) × 6900 = Tk. 1380

0
Updated: 1 week ago
If 10 men or 18 women can do a work in 50 days then how many days would it take 25 men and 15 women to do twice the work?
Created: 2 weeks ago
A
25 days
B
30 days
C
32 days
D
40 days
Question: If 10 men or 18 women can do a work in 50 days then how many days would it take 25 men and 15 women to do twice the work?
Solution:
Here,
10 men = 18 women
∴ 1 men = 18/10 women
∴ 25 men = (18 × 25)/10 women
= 45 women
∴ 25 men and 15 women = (45 + 15) = 60 women
ATQ,
18 women can do the work in 50 days
∴ 1 women can do the work in = (50 × 18) days
∴ 60 women can do the work in (50 × 18)/60 days
= 15 days
Hence to do twice the work time need = (15 × 2) = 30 days

0
Updated: 2 weeks ago
Rafi alone can complete a work in 10 days and Tareq alone can complete it in 15 days. Rafi and Tareq undertook to complete the work for Tk. 7500. With the help of Salman, they finished the work in 5 days. How much should Salman be paid?
Created: 1 week ago
A
Tk. 1200
B
Tk. 1250
C
Tk. 1300
D
Tk. 1380
Question: Rafi alone can complete a work in 10 days and Tareq alone can complete it in 15 days. Rafi and Tareq undertook to complete the work for Tk. 7500. With the help of Salman, they finished the work in 5 days. How much should Salman be paid?
Solution:
Rafi's 1 day work = 1/10
Tareq's 1 day work = 1/15
Rafi + Tareq + Salman's 1 day work = 1/5
∴ Salman's 1 day work = 1/5 - (1/10 + 1/15)
= (6 - 3 - 2)/30
= 1/30
Salman's 5 days work = 5 × 1/30 = 1/6
Salman completed 1/6 of the total work.
∴ He should be paid 1/6 of Tk. 7500
∴ Salman’s payment = 7500 × 1/6 = Tk. 1250

0
Updated: 1 week ago
Hasan can dig 18 holes in 12 minutes. Faruk can dig the same number of holes in only 6 minutes. Hasan digs the first 9 holes, then Faruk digs for 2 minutes, and finally Hasan finishes the remaining holes. How long will it take them to dig 27 holes in total?
Created: 1 week ago
A
10 minutes
B
16 minutes
C
18 minutes
D
21 minutes
Question: Hasan can dig 18 holes in 12 minutes. Faruk can dig the same number of holes in only 6 minutes. Hasan digs the first 9 holes, then Faruk digs for 2 minutes, and finally Hasan finishes the remaining holes. How long will it take them to dig 27 holes in total?
Solution:
Faruk can dig 18 holes in 6 minutes.
∴ In 2 minutes, he can dig = (18 × 2)/6 holes
= 6 holes
Hasan first digs 9 holes.
∴ Total completed = 9 (Hasan) + 6 (Faruk) = 15 holes
Remaining = 27 - 15 = 12 holes
Hasan can dig 18 holes in 12 minutes.
∴ To dig 12 holes, Hasan will take = (12 × 12) / 18 = 8 minutes
Time Hasan spent digging first 9 holes = (12 × 9)/18 = 6 minutes
∴ Total time = 6 (Hasan) + 2 (Faruk) + 8 (Hasan) = 16 minutes

0
Updated: 1 week ago