Solution:
Given,
Interest at 6% for 1 year:
Simple Interest, SI1 = Tk. 360
Interest rate, R = 6%
Time, T = 1 year (initial)

We know,
SI1 = PRT/100
⇒ 360 = (P × 6 × 1)/100
⇒ P = (360 × 100)/6
∴ P = Tk. 6000

So, the original sum (principal) is Tk. 6000.

Now,
Interest at 7% for 1 year:
SI2 = PRT/100
⇒ SI2 = (6000 × 7 × 1)/100
⇒ SI2 = Tk. 420

Additional interest = SI2 - SII
= 420 - 360
= Tk. 60

Solution:
Here,
Principal, P = Tk. 1200
Rate of Interest, r = 5% = 5/100
Time, n = 3 years

We know,
Simple Interest, I = P × n × r
I = 1200 × 3 × (5/100)
I = 1200 × 3 × 5/100
I = 3600 × 5/100
I = 180 Tk.

Now, the Amount after 3 years, A = P + I
A = 1200 + 180
A = 1380 Tk.

∴ The amount after 3 years will be Tk. 1380.

Solution:
Principal (P) = Tk. 5,000
Rate (R) = 10% per annum
Time (T) = 2 years

Simple Interest (SI):
SI = (P × R × T)/100
= (5000 × 10 × 2) / 100
= 100000/100
= Tk. 1000

Compound Interest (CI):
Amount (A) = P × (1 + R/100)T
= 5000 × (1 + 10/100)2
= 5000 × (1.1)2
= 5000 × 1.21
= Tk. 6050

∴ CI = A - P = 6050 - 5000
= Tk. 1050

∴ Difference between CI and SI = 1050 - 1000
= Tk. 50