If 10 men or 18 women can do a work in 50 days then how many days would it take 25 men and 15 women to do twice the work?
A
25 days
B
30 days
C
32 days
D
40 days
উত্তরের বিবরণ
Question: If 10 men or 18 women can do a work in 50 days then how many days would it take 25 men and 15 women to do twice the work?
Solution:
Here,
10 men = 18 women
∴ 1 men = 18/10 women
∴ 25 men = (18 × 25)/10 women
= 45 women
∴ 25 men and 15 women = (45 + 15) = 60 women
ATQ,
18 women can do the work in 50 days
∴ 1 women can do the work in = (50 × 18) days
∴ 60 women can do the work in (50 × 18)/60 days
= 15 days
Hence to do twice the work time need = (15 × 2) = 30 days
0
Updated: 2 months ago
A can complete a piece of work in 36 days, B in 54 days and C in 72 days. All the three began the work together but A left 8 days before the completion of the work and B 12 days before the completion of work. Only C worked up to the end. In how many days was the work completed?
Created: 2 months ago
A
18 days
B
24 days
C
28 days
D
36 days
Question: A can complete a piece of work in 36 days, B in 54 days and C in 72 days. All the three began the work together but A left 8 days before the completion of the work and B 12 days before the completion of work. Only C worked up to the end. In how many days was the work completed?
Solution:
Let the work be completed in y days. C works for y days
Therefore, A works for (y - 8) days
B works for (y - 12) days.
According to the question,
{(y-8)/36} + {(y - 12)/54} + (y/72) = 1
⇒ 6(y - 8) + 4 (y - 12) + 3y = 216
⇒ 6y - 48 + 4y - 48 + 3y = 216
⇒ 13y = 216 + 96 = 312
⇒ y = 312/13
∴ y = 24
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Updated: 2 months ago
In a factory, 20 people can make 20 toys in 15 days working 10 hours per day. Then, in how many days can 25 persons make 30 toys working 20 hours per day?
Created: 2 months ago
A
6 days
B
15 days
C
12 days
D
9 days
Question: In a factory, 20 people can make 20 toys in 15 days working 10 hours per day. Then, in how many days can 25 persons make 30 toys working 20 hours per day?
Solution:
Here,
M1 = 20, M2 = 25
D1 = 15, D2 = ?
T1 = 10, T2 = 20,
W1 = 20 and W2 = 30.
We know,
M1 × D1 × T1 × W2 = M2 × D2 × T2 × W1
⇒ 20 × 15 × 10 × 30 = 25 × D2 × 20 × 20
∴ D2 = 9
Thus, the required day = 9 days
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Updated: 2 months ago
A takes three times as much time as B or twice as much time as C to finish a piece of work. Working together, they can finish the work in 3 days. B can do the work alone in how many days?
Created: 1 month ago
A
14 days
B
8 days
C
6 days
D
10 days
Question: A takes three times as much time as B or twice as much time as C to finish a piece of work. Working together, they can finish the work in 3 days. B can do the work alone in how many days?
Solution:
ধরা যাক,
A, B ও C যথাক্রমে কাজটি শেষ করতে সময় লাগে x, x/3, এবং x/2 দিন।
তারা একসাথে ৩ দিনে কাজ শেষ করে।
অর্থাৎ তাদের একদিনের কাজ হলো 1/3।
∴ A + B + C এর একদিনের কাজ = (1/x) + (3/x) + (2/x)
= (1 + 3 + 2)/x
= 6/x
এখন,
6/x = 1/3
∴ x = 18
∴ B একা কাজ শেষ করতে সময় নেবে = 18/3 = 6 দিন।
0
Updated: 1 month ago
