△ABC- এর BC বাহুকে D পর্যন্ত বর্ধিত করা হলে, ∠ACD এর সমান হবে- 

A

∠A+∠B−∠C 

B

∠A−∠B−∠C

C

∠A+∠B 

D

∠A+∠C

উত্তরের বিবরণ

img

সমাধান:
ধরি ∠A = α, ∠B = β, ∠C = γ।
ত্রিভুজের কোণগুলোর যোগ:

α+β+γ=180\alpha+\beta+\gamma=180^\circ

BC বর্ধিত হওয়ার ফলে ∠ACD ও ∠ACB একই সরলরেখায় পূর্ণকোণ গঠন করে:

ACD+ACB=180\angle ACD+\angle ACB=180^\circ

অতএব

ACD=180γ\angle ACD=180^\circ-\gamma

ত্রিভুজ সমীকরণ থেকে 180γ=α+β180^\circ-\gamma=\alpha+\beta। তাই

ACD=α+β=A+B\angle ACD=\alpha+\beta=\angle A+\angle B

উত্তর: ∠A + ∠B

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Updated: 8 hours ago

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