x - y = 0 হলে x³ - y³ এর মান কত?
A
x² + y²
B
x³ - y³
C
0
D
3
উত্তরের বিবরণ
প্রশ্নঃ x - y = 0 হলে x³ - y³ এর মান কত?
সমাধানঃ
প্রদত্ত, x - y = 0
অর্থাৎ, x = y
এখন,
x³ - y³ = (x - y)(x² + xy + y²)
যেহেতু x - y = 0, তাই
x³ - y³ = 0 × (x² + xy + y²)
অতএব,
x³ - y³ = 0
উত্তরঃ গ) 0
0
Updated: 14 hours ago
An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
Created: 1 month ago
A
10 kg
B
14 kg
C
16 kg
D
20 kg
Question: An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
∴ Nickel that must be added 10 kg.
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
0
Updated: 1 month ago
a + b = 8 এবং a - b = 4 হলে ab = কত?
Created: 3 weeks ago
A
4
B
8
C
10
D
12
সমাধান:
দেওয়া আছে,
a + b = 8 এবং a - b = 4
প্রদত্ত রাশি,
ab = {(a + b)/2}2 - {(a - b)/2}2
= (8/2)2 - (4/2)2
= 42 - 22
= 16 - 4
= 12
0
Updated: 3 weeks ago
যদি
Created: 2 months ago
A
52
B
58
C
60
D
64
0
Updated: 2 months ago
