x+(1/x) = 2 হলে, x/(x²+x-1) এর মান কত?
A
2
B
3
C
1
D
4
উত্তরের বিবরণ
0
Updated: 5 days ago
সমীকরণটিতে p এর মান কত?
Created: 1 month ago
A
2
B
1/4
C
4
D
5/2
গণিত
অসমতা (Inequality)
বীজগণিত (Algebra)
সরল সমীকরণ (Simple/linear equation)
সরল-সহসমীকরণ (Simultaneous linear equations)
প্রশ্ন: 
সমীকরণটিতে p এর মান কত?
সমাধান:
0
Updated: 1 month ago
যদি |2x + 5| < 3 হলে, m এবং n এর কোন মানের জন্য m < 3x - 2 < n হবে?
Created: 5 months ago
A
m = - 5, n = 15
B
m = - 14, n = - 5
C
m = - 2, n = - 14
D
m = 4, n= 12
প্রশ্ন: যদি |2x + 5| < 3 হলে, m এবং n এর কোন মানের জন্য m < 3x - 2 < n হবে?
সমাধান:
|2x + 5| < 3
⇒ - 3 < 2x + 5 < 3
⇒ - 3 - 5 < 2x + 5 - 5 < 3 - 5
⇒ - 8 < 2x < - 2
⇒ - 4 < x < - 1
⇒ - 12 < 3x < - 3
⇒ - 12 - 2 < 3x - 2 < - 3 - 2
∴ - 14 < 3x - 2 < - 5
m < 3x - 2 < n এর সাথে তুলনা করে পাই,
∴ m = - 14 এবং n = - 5
0
Updated: 5 months ago
An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
Created: 1 month ago
A
10 kg
B
14 kg
C
16 kg
D
20 kg
Question: An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
∴ Nickel that must be added 10 kg.
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
0
Updated: 1 month ago
