Question: A is five times as old as B. 5 years ago, A was ten times as old as B. What will be the sum of their ages after 8 years?

সমাধান:
ধরি,
B-এর বর্তমান বয়স = x বছর
A-এর বর্তমান বয়স = 5x বছর

5 বছর আগে,
B-এর বয়স ছিল = (x - 5) বছর
A-এর বয়স ছিল = (5x - 5) বছর

প্রশ্নমতে,
5x - 5 = 10(x - 5)
⇒ 5x - 5 = 10x - 50
⇒ 50 - 5 = 10x - 5x
⇒ 45 = 5x
⇒ x = 45/5
∴ x = 9

সুতরাং, B-এর বর্তমান বয়স 9 বছর এবং A-এর বর্তমান বয়স 5 × 9 = 45 বছর।

8 বছর পর,
B-এর বয়স হবে = 9 + 8 = 17 বছর
A-এর বয়স হবে = 45 + 8 = 53 বছর

∴ 8 বছর পর তাদের বয়সের সমষ্টি হবে = 17 + 53 = 70 বছর।

Question: Sachin is younger than Rohan by four years. If their ages are in the respective ratio of 7 : 9, how old is Sachin?

Solution:
Given that,
Sachin is 4 years younger than Rohan
Their ages are in the ratio 7 : 9

Let their ages are,
Sachin = 7x
Rohan = 9x

ATQ,
9x - 7x = 4
⇒ 2x = 4
∴ x = 2

Sachin age is = 7x = 7 × 2 = 14​ years

Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 42, then how old is B?

Solution:

Let the age of C be = x years 

 Then, age of B = 2x years.

age of A = (2x + 2) years.

According to the question,

(2x + 2) + 2x + x = 42

⇒ 5x + 2 = 42

⇒ 5x = 42 - 2

⇒ 5x = 40

⇒ x = 40/5

⇒ x = 8

Hence, age of B = 2x = (2 × 8) years = 16 years.