যদি logx2 = a এবং logx3 = b হয়, তাহলে logx72 = কত?
A
a + 2b
B
2a - 3b
C
a + 3b
D
3a + 2b
উত্তরের বিবরণ
সমাধান:
দেওয়া আছে, logx2 = a এবং logx3 = b
logx72
= logx(8 × 9)
= logx(23 × 32)
= logx(23) + logx(32) [log(mn) = logm + logn]
= 3logx2 + 2logx3
= 3a + 2b [মান বসিয়ে]

0
Updated: 3 days ago
2log105 + log1036 - log109 =?
Created: 3 weeks ago
A
2
B
100
C
37
D
4.6
2log105 + log1036 - log109 = log1052 + log1062- log1032 [ plogkM = logkMp]
= log10 {(52×62)/32} [logkM + logkN = logk(MN), logkM – logkN = logk(M/N)]= log10{(25 × 36)/9}= log10100= log10102= 2log1010= 2.1= 2
= log10 {(52×62)/32} [logkM + logkN = logk(MN), logkM – logkN = logk(M/N)]

0
Updated: 3 weeks ago
Created: 6 hours ago
A
1/2
B
3/5
C
2/5
D
1/3
প্রশ্ন:
সমাধান:

0
Updated: 6 hours ago