যদি logx2 = a এবং logx3 = b হয়, তাহলে logx72 = কত?

A

a + 2b

B

2a - 3b

C

a + 3b 

D

3a + 2b

উত্তরের বিবরণ

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সমাধান:
দেওয়া আছে, logx2 = a এবং logx3 = b
logx72
= logx(8 × 9)
= logx(23 × 32)
= logx(23) + logx(32) [log(mn) = logm + logn]
= 3logx2 + 2logx3
= 3a + 2b [মান বসিয়ে]

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Updated: 3 days ago

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