loga(b3) = 3x এবং logb(a3) = 3y হলে, xy = কত?

A

9

B

1

C

xy


D

5

উত্তরের বিবরণ

img
সমাধান:
দেওয়া আছে, loga(b3) = 3x
⇒ 3loga(b) = 3x
⇒ loga(b) = x
আবার, logb(a3) = 3y
⇒ 3logb(a) = 3y
⇒ logb(a) = y
আমরা জানি, loga(b) × logb(a) = 1
সুতরাং, xy = loga(b) × logb(a)
∴ xy = 1
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