A bag contains 7 green balls, 8 blue balls, and 5 yellow balls. One ball is drawn at random. What is the probability that the ball drawn is neither green nor yellow?

A

7/20

B

1/2

C

2/5

D

1/4

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Question: A bag contains 7 green balls, 8 blue balls, and 5 yellow balls. One ball is drawn at random. What is the probability that the ball drawn is neither green nor yellow?

​Solution:

​Total balls = 7 + 8 + 5 = 20

​Favorable outcomes = balls that are neither green nor yellow, that mean blue balls = 8

P(blue) = Favorable outcomes​/total outcomes​ = 8/20 = 2/5

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Updated: 13 hours ago

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