সমাধান:

মুদ্রা তিনবার নিক্ষেপ করলে সম্ভাব্য ফলাফলগুলো হবে:

= HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

মোট সম্ভাব্য ফলাফল = ৮ টি

এর মধ্যে কমপক্ষে ২ টি T (TAIL) আসলে অনুকূল ফলাফল হয় = HTT, THT, TTH TTT অর্থাৎ ৪ টি

মুদ্রাকে ৩ বার নিক্ষেপ করা হলে কমপক্ষে ২ টি T (TAIL)) আসার সম্ভাবনা = ৪/৮ = ১/২

Question: Three unbiased coins are tossed. What is the probability of getting at least 2 heads?

Solution:
Total outcomes = {TTT, TTH,THT, HTT, THH, HTH, HHT, HHH} = 8
Favorable outcomes = {HHT, HTH, THH, HHH} = 4

So, the probability of getting at least 2 heads = Favorable outcomes/Total outcomes
= 4/8 = 1/2

Question: How many words can be formed by using the letters from the word 'DRIVER' such that all the vowels are never together?

Solution:
We assume all the vowels to be a single character, i.e., 'IE' is a single character.
So, now we have 5 characters in the word, namely, D, R, V, R, and IE.

But, R occurs 2 times.
Number of possible arrangements = 5!/2! = 60

Now, 
​the two vowels can be arranged in 2! = 2 ways.

Total number of possible words such that the vowels are always together = 60 × 2 = 120

Total number of possible words = 6!/2! = 720/2 = 360

Therefore, the total number of possible words such that the vowels are never together = 360 - 120 = 240