3x + (3/x) = 15 হলে, x2 + (1/x2) এর মান কত?
A
18
B
23
C
34
D
30
উত্তরের বিবরণ
প্রশ্ন: 3x + (3/x) = 15 হলে, x2 + (1/x2) এর মান কত?
সমাধান:
দেওয়া আছে,
3x + (3/x) = 15
⇒ 3(x + 1/x) = 15
∴ x + 1/x = 5
প্রদত্ত রাশি: x2 + (1/x2)
= {x + (1/x)}2 - 2 . x . 1/x
= 52 - 2
= 25 - 2
= 23
0
Updated: 1 month ago
If A = 2, B
= 4, C = 6, D = 8, E = 10 and so on, what is the meaning of following number
40, 18, 14, 10, 36
Created: 1 month ago
A
RIVER
B
TIGER
C
FIGHT
D
RIGHT
Question: If A = 2, B = 4, C = 6, D = 8, E = 10 and so on, what is the meaning of following number 40, 18, 14, 10, 36
Solution:
Given,
A = 2, B = 4, C = 6, D = 8, E = 10.......
∴ Each code = Letter position × 2
So
40 ÷ 2 = 20 → T
18 ÷ 2 = 9 → I
14 ÷ 2 = 7 → G
10 ÷ 2 = 5 → E
36 ÷ 2 = 18 → R
the meaning of following number = TIGER
0
Updated: 2 weeks ago
In a class, 30 students play basketball, 20 students play volleyball, and 8 students play both. 12 students play neither basketball nor volleyball. What is the total number of students in the class?
Created: 1 month ago
A
45
B
72
C
60
D
54
Question: In a class, 30 students play basketball, 20 students play volleyball, and 8 students play both. 12 students play neither basketball nor volleyball. What is the total number of students in the class?
Solution:
Number of students who play basketball, n(B) = 30
Number of students who play volleyball, n(V) = 20
Number of students who play both basketball and volleyball, n(B ∩ V) = 8
Number of students who play neither = 12
n(B ∪ V) = n(B) + n(V) - n(B ∩ V)
= 30 + 20 - 8 = 42
Total students in the class = students who play basketball or volleyball + students who play neither
n(U) = n(B ∪ V) + neither = 42 + 12 = 54
∴ Total 54 students in the class.
0
Updated: 1 month ago
একটি কোণকের বক্রতলের ব্যাসার্ধ 7 সে.মি. এবং উচ্চতা 27 সে.মি. হলে কোণকের আয়তন কত?
Created: 1 month ago
A
1256 ঘন সে.মি.
B
1266 ঘন সে.মি.
C
1336 ঘন সে.মি.
D
1386 ঘন সে.মি.
প্রশ্ন: একটি কোণকের বক্রতলের ব্যাসার্ধ 7 সে.মি. এবং উচ্চতা 27 সে.মি. হলে কোণকের আয়তন কত?
সমাধান:
দেওয়া আছে,
কোণকের বক্রতলের ব্যাসার্ধ, r = 7 সে.মি.
উচ্চতা, h = 27 সে.মি.
আমরা জানি,
কোণকের আয়তন,
= (1/3)πr2h
= (1/3) × (22/7) × (7)2 × 27 ঘন সে.মি.
= (22/7) × 49 × 9 ঘন সে.মি.
= 22 × 63 ঘন সে.মি.
= 1386 ঘন সে.মি.
0
Updated: 1 month ago