a ≤ (a/2) + 3 এর সমাধান কত?
A
a ≤ 2
B
a ≤ 1
C
a ≤ 6
D
a ≤ 3
উত্তরের বিবরণ
সমাধান:
a ≤ (a/2) + 3
⇒ 2a ≤ 2{(a/2) + 3}
⇒ 2a ≤ a + 6
⇒ 2a - a ≤ a + 6 - a
⇒ a ≤ 6
0
Updated: 1 month ago
What is the 9th term of the sequence : - 2, - 4, - 6, ............................ , - 100?
Created: 4 weeks ago
A
- 16
B
- 18
C
- 20
D
22
Question: What is the 9th term of the sequence : - 2, - 4, - 6, ............................ , - 100?
Solution:
Here,
- 4 - (- 2) = - 4 + 2 = - 2
- 6 - (- 4) = - 6 + 4 = - 2
∴ d = - 2
a = - 2
n = 9
∴ The 9th term of the sequence = a + (n - 1)d
= - 2 + (9 - 1) (- 2)
= - 2 + 8 (- 2)
= - 2 - 16
= - 18
0
Updated: 4 weeks ago
A company's profits have doubled for each of the last 5 years. If the total profits for the last 5 years were Tk. 62 lacs, what were the profits in the first year?
Created: 4 weeks ago
A
Tk. 1,00,000
B
Tk. 2,00,000
C
Tk. 3,00,000
D
Tk. 4,00,000
Solution:
ধরা যাক, প্রথম বছরের লাভ P টাকা। যেহেতু লাভ প্রতি বছর দ্বিগুণ হয়েছে,
সুতরাং, গত 5 বছরের লাভের পরিমাণ ছিল: P, 2P, 4P, 8P, এবং 16P।
প্রশ্ন অনুযায়ী, গত 5 বছরের মোট লাভ ছিল 62 লক্ষ টাকা।
∴ P + 2P + 4P + 8P + 16P = 62,00,000
⇒ 31P = 62,00,000
⇒ P = 62,00,000 / 31
⇒ P = 2,00,000
সুতরাং, প্রথম বছরে লাভ ছিল 2,00,000 টাকা।
ধরা যাক, প্রথম বছরের লাভ P টাকা। যেহেতু লাভ প্রতি বছর দ্বিগুণ হয়েছে,
সুতরাং, গত 5 বছরের লাভের পরিমাণ ছিল: P, 2P, 4P, 8P, এবং 16P।
প্রশ্ন অনুযায়ী, গত 5 বছরের মোট লাভ ছিল 62 লক্ষ টাকা।
∴ P + 2P + 4P + 8P + 16P = 62,00,000
⇒ 31P = 62,00,000
⇒ P = 62,00,000 / 31
⇒ P = 2,00,000
সুতরাং, প্রথম বছরে লাভ ছিল 2,00,000 টাকা।
0
Updated: 4 weeks ago
Two cards are drawn at random and without replacement from a standard deck of 52 cards. What is the probability that both cards are face cards?
Created: 1 month ago
A
1/26
B
1/13
C
5/52
D
11/221
Question: Two cards are drawn at random and without replacement from a standard deck of 52 cards. What is the probability that both cards are face cards?
Solution:
Total card = 52
Total face card = 3 × 4 = 12
Total ways to choose 2 cards from 52 = 52C2 = (52 × 51)/2 = 1326
Total ways to choose 2 face cards from 12 = 12C2 = (12 × 11)/2 = 66
∴ So, the probability that both cards are face cards = 66/1326
= (2 × 3 × 11)/(2 × 3 × 221)
= 11/221
0
Updated: 1 month ago
