Find the simple interest on BDT 12000 at 8% per annum for 6 months.
A
Tk. 480
B
Tk. 560
C
Tk. 400
D
Tk. 420
উত্তরের বিবরণ
Question: Find the simple interest on BDT 12000 at 8% per annum for 6 months.
Solution:
Principal, P = 12000 Taka
Time, n = 6 months = 6/12 = 1/2 years
Rate of interest, r = 8% = 8/100
Simple Interest, I = P × n × r
= 12000 × (1/2) × (8/100)
= (12000 × 1 × 8)/(2 × 100)
= 96000/200
= 480
∴ The simple interest is Tk. 480.
0
Updated: 1 month ago
A fruit seller sells 20 oranges for Tk. 900 and suffers a loss equal to the cost price of 5 oranges. Find the cost price of one orange.
Created: 1 month ago
A
Tk. 55
B
Tk. 60
C
Tk. 42
D
Tk. 62
Question: A fruit seller sells 20 oranges for Tk. 900 and suffers a loss equal to the cost price of 5 oranges. Find the cost price of one orange.
Solution:
Let,
cost price of 1 orange is = Tk. x
∴ cost price of 20 oranges is = Tk. 20x
∴ cost price of 5 oranges is = Tk. 5x
We know,
Cost price - Selling price = Loss
20x - 900 = 5x
⇒ 20x - 5x = 900
⇒ 15x = 900
⇒ x = 900/15
∴ x = 60
∴ Cost price of 1 orange is Tk. 60
0
Updated: 1 month ago
In how many years will Tk. 750 amount to Tk. 900 at 4% simple interest per annum?
Created: 3 months ago
A
3.5 years
B
3 years
C
4.5 years
D
5 years
Solution:
Simple Interest = Amount - Principal
= 900 - 750
= 150
Here,
Principal, P = 750
Interest Rate, R = 4%
SI = 150
Time, T = ?
SI = PRT/100
⇒ T = (SI × 100)/(P × R)
= (150 × 100)/(750 × 4)
= 15000/3000
= 5 years
0
Updated: 3 months ago
A bank offers 5% compound interest calculated half-yearly. A customer deposits Tk. 1600 on 1st January and another Tk. 1600 on 1st July of the same year. How much interest will he earn at the end of the year?
Created: 3 months ago
A
Tk. 129
B
Tk. 121
C
Tk. 118
D
Tk. 132
Solution:
Here,
Half-yearly interest rate = 5% ÷ 2 = (5/2)%
Now,
The first deposit of Tk. 1600 was made on 1st January.
It stays for 12 months, so it earns interest twice, once after 6 months, and again after 12 months.
So, it earns interest for 2 times (i.e., 2 half-years).
∴ A1 = P(1 + r/100)n
= 1600 × {1 + 5/(2 × 100)}2
= 1600 × {1 + (1/40)}2
= 1600 × (41/40) × (41/40)
= 1600 × 1681/1600
= 1681
Now,
The second deposit of Tk. 1600 was made on 1st July.
It stays for 6 months, so it earns interest only once (1 half-year).
∴ A2 = P(1 + r/100)n
= 1600 × (1 + 1/40)1
= 1600 × (41/40)
= 1640
Total amount = 1681 + 1640 = 3321
Total money deposited = 1600 + 1600 = 3200
∴Interest earned = 3321 - 3200 = Tk. 121
∴ The customer would have gained Tk. 121 by way of interest.
0
Updated: 3 months ago
