The ratio of the present ages of a mother and son is 7 : 2. After 7 years, the ratio of their ages becomes 8 : 3. What will be the ratio of their ages after 11 years?

A

12 : 5

B

12 : 7

C

10 : 7

D

13 : 6

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Question: The ratio of the present ages of a mother and son is 7 : 2. After 7 years, the ratio of their ages becomes 8 : 3. What will be the ratio of their ages after 11 years?

Solution:
Let,
The present age of the mother = 7x years
The present age of the son = 2x years

After 7 years, their ages will be:
Mother = (7x + 7) years
Son = (2x + 7) years

According to the question,
(7x + 7)/(2x + 7) = 8/3
3(7x + 7) = 8(2x + 7)
21x + 21 = 16x + 56
21x - 16x = 56 - 21
5x = 35
x = 35/5
x = 7

Present age of mother = 7 × 7 = 49 years
Present age of son = 2 × 7 = 14 years

Now, after 11 years,
Mother's age = 49 + 11 = 60 years
Son's age = 14 + 11 = 25 years

The ratio of their ages after 11 years,
= 60 : 25
= 12 : 5

 

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Updated: 8 hours ago

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