log272 - log218 + log28 = কত?

A

9

B

3

C

7

D

5

উত্তরের বিবরণ

img
সমাধান:
= log272 - log218 + log28
= log2(72 × 8) - log218 
= log2{(72 × 8)/18}
= log232
= log225
= 5log22
= 5  ; [ log22 = 1]
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Updated: 1 month ago

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প্রশ্ন:


Created: 2 months ago

A

- 2log

B

log2

C

2

D

- 1

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