একটি ছক্কা কে একবার নিক্ষেপ করা হলে 2 থেকে বড় সংখ্যা না পাওয়ার সম্ভাবনা কত?
A
1/2
B
1/3
C
5/6
D
2/3
উত্তরের বিবরণ
প্রশ্ন: একটি ছক্কা কে একবার নিক্ষেপ করা হলে 2 থেকে বড় সংখ্যা না পাওয়ার সম্ভাবনা কত?
সমাধান:
একটি ছক্কা একবার নিক্ষেপ করা হলে মোট নমুনা ক্ষেত্র হবে = 61 = 6 টি
নমুনা ক্ষেত্র গুলো হবে = 1, 2, 3, 4, 5, 6
এখন, সংখ্যা গুলোর মধ্যে 2 থেকে বড় সংখ্যা গুলো হলো = 3, 4, 5, 6 অর্থাৎ 4 টি ।
∴ ছক্কা একবার নিক্ষেপ করা হলে 2 থেকে বড় সংখ্যা পাওয়ার সম্ভাবনা = অনুকূল ঘটনার সংখ্যা/মোট ঘটনা সংখ্যা = 4/6 = 2/3
∴ 2 থেকে বড় সংখ্যা না পাওয়ার সম্ভাবনা = 1 - (2/3) = (3 - 2)/3 = 1/3
বিকল্প:
ছক্কায় 2 থেকে বড় নয় এমন সংখ্যা হলো- 1, 2 অর্থাৎ 2 টি।
∴ ছক্কা একবার নিক্ষেপ করা হলে 2 থেকে বড় সংখ্যা না আসার সম্ভাবনা = 2/6 = 1/3
0
Updated: 1 month ago
Fahim is younger than Nabila but older than Ritu. Shanti is older than Fahim. Nabila is the second-oldest person among them. Labib is younger than Ritu. Who is the third-oldest among them?
Created: 1 month ago
A
Ritu
B
Shanti
C
Fahim
D
Labib
First statement: Nabila > Fahim > Ritu
• Second statement: Shanti > Fahim
• Third statement: Nabila is the second oldest, meaning one person is older than Nabila.
Since both Shanti and Nabila are older than Fahim, and Nabila is the second-oldest, Shanti must be the oldest. Therefore, Shanti > Nabila > Fahim
• Fourth statement: Ritu > Labib
• Putting everyone together: Shanti > Nabila > Fahim > Ritu > Labib
∴ The third-oldest person is Fahim.
• Second statement: Shanti > Fahim
• Third statement: Nabila is the second oldest, meaning one person is older than Nabila.
Since both Shanti and Nabila are older than Fahim, and Nabila is the second-oldest, Shanti must be the oldest. Therefore, Shanti > Nabila > Fahim
• Fourth statement: Ritu > Labib
• Putting everyone together: Shanti > Nabila > Fahim > Ritu > Labib
∴ The third-oldest person is Fahim.
0
Updated: 1 month ago
A fair coin is tossed 4 times. What is the probability of getting exactly 3 heads?
Created: 3 weeks ago
A
1/2
B
1/3
C
1/4
D
1/5
Question: A fair coin is tossed 4 times. What is the probability of getting exactly 3 heads?
Solution:
For 4 tosses, the total number of possible outcomes is = 24 = 16
The number of ways to choose 3 Heads out of 4 tosses is = 4C3 = 4
∴ Probability of getting exactly 3 heads = 4/16 = 1/4
0
Updated: 3 weeks ago
A bag contains 6 red, 4 green, and 5 blue balls. Two balls are drawn without replacement. What is the probability that the first ball is red and the second ball is green or blue?
Created: 1 month ago
A
13/15
B
9/35
C
21/65
D
12/35
Question: A bag contains 6 red, 4 green, and 5 blue balls. Two balls are drawn without replacement. What is the probability that the first ball is red and the second ball is green or blue?
Solution:
Given that,
Red balls = 6
Green balls = 4
Blue balls = 5
Total balls = 6 + 4 + 5 = 15
We know
Probability = Favorable outcomes/Total outcomes
Now,
First ball is Red = 6/15 = 2/5
If first is red, then remaining balls = 14
Second ball is Green or Blue = (4 + 5)/14 = 9/14
∴ Required probability = (2/5) × (9/14)
= 9/35
∴ The required probability is 9/35.
0
Updated: 1 month ago