The ratio between the speeds of two trains is 5 : 8. If the second train runs 600 km in 5 hours, then the speed of the first train is -
A
100 kmph
B
95 kmph
C
80 kmph
D
75 kmph
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Question: The ratio between the speeds of two trains is 5 : 8. If the second train runs 600 km in 5 hours, then the speed of the first train is -
Solution:
Let the speed of the trains are 5x and 8x
the speed of the second train = 600/5 kmph = 120 kmph
∴ 8x = 120
x = 15
∴ speed of first train = 5x = 75 kmph
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Updated: 1 month ago
A boat can travel 48 km upstream in 6 hours. If the speed of the stream is 2 km/hr, how much time will the boat take to cover a distance of 120 km downstream?
Created: 1 month ago
A
20 hours
B
18 hours
C
10 hours
D
19 hours
Question: A boat can travel 48 km upstream in 6 hours. If the speed of the stream is 2 km/hr, how much time will the boat take to cover a distance of 120 km downstream?
Solution:
Distance covered by a boat in 6 hours = 48 km
Rate upstream of boat = 48/6
= 8 km/hr
Now,
Speed of stream = 2 km/hr
∴ Speed of boat in still water = (8 + 2)
= 10 km/hr
∴ Rate downstream of boat = (10 + 2) km/hr
= 12 km/hr
∴ Time taken in covering 120 km distance = 120/12
= 10 hours
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Updated: 1 month ago
A man can row upstream at 10 kmph and downstream at 20 kmph. Find the man's rate in still water and the rate of the stream.
Created: 1 month ago
A
12 kmph , 7 kmph
B
15 kmph , 5 kmph
C
15 kmph , 12 kmph
D
10 kmph , 5 kmph
Question: A man can row upstream at 10 kmph and downstream at 20 kmph. Find the man's rate in still water and the rate of the stream.
Solution:
If a is rate downstream and b is rate upstream
Rate in still water = (a + b)/2
Rate of current = (a - b)/2
Rate in still water = (20 + 10)/2 = 15 kmph
Rate of current = (20 - 10)/2 = 5 kmph
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Updated: 1 month ago
A train passes two bridges of length 800 m and 400 m in 100 seconds and 60 seconds respectively. The length of the train is-
Created: 1 month ago
A
350 m
B
450 m
C
300 m
D
200 m
Question: A train passes two bridges of length 800 m and 400 m in 100 seconds and 60 seconds respectively. The length of the train is-
Solution:
Let the length of the train is x m and speed is s.
ATQ,
s = (x + 800)/100 and,
s = (x + 400)/60
∴ (x + 800)/100 = (x + 400)/60
or, 60x + 48000 = 100x + 40000
or, 40x = 8000
or, x = 200 m
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Updated: 1 month ago