An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
A
10 kg
B
14 kg
C
16 kg
D
20 kg
উত্তরের বিবরণ
Question: An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
∴ Nickel that must be added 10 kg.
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
0
Updated: 1 month ago
logb a1/4 logc b3 loga c4 এর সমাধান কোনটি?
Created: 1 month ago
A
1
B
1/4
C
3
D
loga 2
প্রশ্ন: logb a1/4 logc b3 loga c4 এর সমাধান কোনটি?
সমাধান:
logb a1/4 logc b3 loga c4
= {(1/4) logb a} × (3 logc b) × (4 loga c)
= {(1/4) × 3 × 4} logb a × logc b × loga c
= 3 logc a × loga c [ যেহেতু loga b × logb a = logb b]
= 3 loga a
= 3 × 1
= 3
0
Updated: 1 month ago
Solve: x4 -
5x2 + 4 = 0
Created: 1 month ago
A
± 1, ± 5
B
± 3, ± 2
C
± 1, ± 2
D
± 4, ± 1
Question: Solve: x4 - 5x2 + 4 = 0
Solution:
Given,
x4 - 5x2 + 4 = 0
(x2)2 - 5x2 + 4 = 0
Let
x2 = a
∴ a2 - 5a + 4 = 0
⇒ a2 - 4a - a + 4 = 0
⇒ a(a - 4) - 1(a - 4) = 0
⇒ (a - 4)(a - 1) = 0
∴ a - 4 = 0
⇒ a = 4
⇒ x2 = 4
∴ x = ± 2
and,
a - 1 = 0
⇒ a = 1
⇒ x2 = 1
∴ x = ± 1
∴ x = ± 1, ± 2
0
Updated: 5 days ago
f(x) = x3 - mx2 + 7x - 10 হয়, তাহলে m এর কোন মানের জন্য f(2) = 0 হবে?
Created: 1 month ago
A
- 1
B
4
C
- 2
D
3
প্রশ্ন: f(x) = x3 - mx2 + 7x - 10 হয়, তাহলে m এর কোন মানের জন্য f(2) = 0 হবে?
সমাধান:
দেওয়া আছে,
f(x) = x3 - mx2 + 7x - 10
= (2)3 - m(2)2 + 7(2) - 10
= 8 - 4m + 14 - 10
= 12 - 4m
এখন,
f(2) = 0
⇒ 12 - 4m = 0
⇒ 4m = 12
∴ m = 3
0
Updated: 1 month ago
