In what ratio should a mixture of 20% alcohol strength be mixed with a mixture of 60% alcohol strength to get a mixture of 50% alcohol strength?

A

1 : 2

B

3 : 2

C

1 : 3

D

2 : 3

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Question: In what ratio should a mixture of 20% alcohol strength be mixed with a mixture of 60% alcohol strength to get a mixture of 50% alcohol strength?

Solution:
Let the ratio be 1 : x
Then according to the question
⇒ 20 × 1 + 60x = (1 + x) 50
⇒ 20 + 60x = 50 + 50x
⇒ 60x - 50x = 50 - 20
⇒ 10x = 30
⇒ x = 3

∴ the ratio is 1 : 3

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Updated: 4 days ago

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