An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
A
10 kg
B
14 kg
C
16 kg
D
20 kg
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Question: An alloy contains Copper, Zinc and Nickel in the ratio of 5 : 3 : 2. The quantity of Nickel that must be added to 100 kg of this alloy to have the new ratio 5 : 3 : 3 is-
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
∴ Nickel that must be added 10 kg.
Solution:
Given that,
An alloy contains Copper : Zinc : Nickel = 5 : 3 : 2
Total weight = 100 kg
Now, Sum of the ratio, 5 + 3 + 2 = 10
Copper = (5/10) × 100 = 50 kg
Zinc = (3/10) × 100 = 30 kg
Nickel = (2/10) × 100 = 20 kg
Now, Let the amount of Nickel to be added be x kg
Then, new quantity of Nickel = 20 + x
And Copper : Zinc : Nickel = 5 : 3 : 3
ATQ,
50/5 : 30/3 : (20 + x)/3
Now taking last two ratio, then we get,
⇒ 30/3 = (20 + x)/3
⇒ 30 = 20 + x
⇒ x = 30 - 20
∴ x = 10
0
Updated: 13 hours ago
2y = 2x - 4 এবং 4x - 5y = 3 হলে (x, y) এর মান কত?
Created: 2 weeks ago
A
(5, 6)
B
(6, 8)
C
(7, 5)
D
(7, 8)
প্রশ্ন: 2y = 2x - 4 এবং 4x - 5y = 3 হলে (x, y) এর মান কত?
সমাধান:
দেওয়া আছে,
2y = 2x - 4
⇒ y = (2x - 4)/2
⇒ y = x - 2 ..............(1)
এখন,
4x - 5y = 3
⇒ 4x = 3 + 5y
⇒ 4x = 3 + 5(x - 2)
⇒ 4x = 3 + 5x - 10
⇒ 4x = 5x - 7
⇒ 5x - 4x = 7
⇒ x = 7
x এর মান (1) নং সমীকরণে বসিয়ে পাই,
y = (7 - 2) = 5
∴ (x, y) = (7, 5)
0
Updated: 2 weeks ago
(5x/6) + 2 = (2x/3) + 4 হলে, x এর মান কত?
Created: 2 days ago
A
8
B
10
C
12
D
15
প্রশ্ন: (5x/6) + 2 = (2x/3) + 4 হলে, x এর মান কত?
সমাধান:
(5x/6) + 2 = (2x/3) + 4
বা, (5x/6) - (2x/3) = 4 - 2
বা, (5x - 4x)/6 = 2
বা, x/6 = 2
বা, x = 2 × 6
∴ x = 12
0
Updated: 2 days ago
যদি x4 - x2 + 1 = 0 হয়, তবে, x3 + 1/x3 = কত?
Created: 1 week ago
A
3
B
2
C
1
D
0
প্রশ্ন: যদি x4 - x2 + 1 = 0 হয়, তবে, x3 + 1/x3 = কত?
সমাধান:
x4 - x2 + 1 = 0
⇒ x4 +1 = x2
⇒ (x4 + 1)/x2 = 1
⇒ x2 + 1/x2 = 1
⇒ (x + 1/x)2 -2.x.1/x =1
∴ x+ (1/x) = √3
x3 + (1/x)3
= {x + (1/x)}3 - 3.x. (1/x) {x + (1/x)}
= (√3)3 - 3. √3
= 3√3 - 3√3
= 0
0
Updated: 1 week ago
