A
cosec2θ
B
tan2θ
C
sec2θ. cosec2θ
D
tan2θ. cot2θ
উত্তরের বিবরণ
সমাধান:
sec2θ + cosec2θ
= (1/cos2θ) + (1/sin2θ)
= (sin2θ + cos2θ)/(cos2θ. sin2θ)
= 1/(cos2θ. sin2θ)
= (1/cos2θ). (1/sin2θ)
= sec2θ. cosec2θ
0
Updated: 1 day ago
sinθ = 3/5 হলে, tanθ এর মান কত?
Created: 3 weeks ago
A
1/3
B
4/3
C
5/4
D
3/4
0
Updated: 3 weeks ago
যদি (5sinθ + 2cosθ)/(5sinθ - 2cosθ) = 3 হয়, তাহলে tanθ = ?
Created: 1 day ago
A
3/4
B
5/3
C
4/5
D
2/3
প্রশ্ন: যদি (5sinθ + 2cosθ)/(5sinθ - 2cosθ) = 3 হয়, তাহলে tanθ = ?
সমাধান:
দেওয়া আছে,
(5sinθ + 2cosθ)/(5sinθ - 2cosθ) = 3
⇒ (5sinθ + 2cosθ + 5sinθ - 2cosθ)/(5sinθ + 2cosθ - 5sinθ + 2cosθ) = (3 + 1)/(3 - 1) [যোজন-বিয়োজন করে]
⇒ (10sinθ)/(4cosθ) = 4/2
⇒ (5sinθ)/(2cosθ) = 2
⇒ sinθ/cosθ = (2 × 2)/5
⇒ tanθ = 4/5
∴ tanθ = 4/5
0
Updated: 1 day ago
sinA + sin2A = 1 হলে cos2A + cos4A = কত?
Created: 1 day ago
A
1
B
4
C
3
D
2
সমাধান:
দেওয়া আছে,
sinA + sin2A = 1
বা, sinA = 1 - sin2A
∴ sinA = cos2A
এখন,
cos2A + cos4A
= cos2A + (cos2A)2
= cos2A + (sinA)2
= cos2A + sin2A
= sin2A + cos2A
= 1
0
Updated: 1 day ago
